Arrays are data structure in which identical data types are stored. The arrays occupy the memory depending upon their size and have contiguous area of memory. We can access the arrays using the array index.

To declare arrays, we have to give their data type, name and size. These are fixed-size arrays. The declaration of arrays is as follows:

data_type    array_name [size] ;

Consider the following program:

void main(  )


int x[6]; 

  int j;

    for(j = 0; j < 6; j++) 

         x[j] = 2 * j;

We have declared an intarray of six elements and initialized it in the loop.

Let’s revise some of the array concepts. The declaration of array is as int x[6]; or float x[6]; or double x[6]; You have already done these in your programming assignments. An array is collection of cells of the same type. In the above program, we have array x of type int of six elements. We can only store integers in this array. We cannot put int in first location, float in second location and double in third location. What is x? xis a name of collection of items. Its individual items are numbered from zero to one less than array size. To access a cell, use the array name and an index as under:
           x[0], x[1], x[2], x[3], x[4], x[5]
To manipulate the first element, we will use the index zero as x[0] and so on. 
Array occupies contiguous memory area in the computer. In case of the above example, if some location is assigned to x[0], the next location can not contain data other than x[1]. The computer memory can be thought of as an array. It is a very big array. Suppose a computer has memory of 2MB, you can think it as an array of size 2 million and the size of each item is 32 bits. You will study in detail about it in the computer organization, and Assembly language courses. In this array, we will put our programs, data and other things.
In the above program, we have declared an array named x. ‘x’ is an array’s name but there is no variable x. ‘x’ is not an lvalue
If some variable can be written on the left- hand side of an assignment statement, this is lvaluevariable. It means it has some memory associated with it and some value can be assigned to it. For example, if we have the code  
          int a, b;
It can be written as b = 2;
It means that put 2 in the memory location named b.We can also write as a = b; it means whatever b has assign it to a, that is a copy operation. If we write as a = 5; it means put the number 5 in the memory location which is named as a. But we cannot write 2 = a; that is to put at number 2 what ever the value of a is. Why can’t we do that? Number 2 is a constant. If we allow assignment to constants what will happen? Suppose ‘a’ has the value number 3. Now we assigned number 2 the number 3 i.e. all the number 2 will become number 3 and the result of 2 + 2 will become 6. Therefore it is not allowed.
x’ is a name of array and  not an lvalue. So it cannot be used on the left hand side in an assignment statement. Consider the following statements
int x[6];   
int n;
x[0] = 5;   x[1] = 2;
x = 3;                                // not allowed
x = a + b;                            // not allowed
x = &n;                           // not allowed
In the above code snippet, we have declared an array x of int. Now we can assign values to the elements of xas x[0] = 5 or x[1] = 2 and so on. The last three statements are not allowed. What does the statement x = 3; mean? As x is a name of array and this statement is not clear, what we are trying to do here? Are we trying to assign 3 to each element of the array? This statement is not clear. Resultantly, it can not be allowed. The statement x = a + b is also not allowed. There is nothing wrong with a + b. But we cannot assign the sum of values of a and b to x. In the statement x = &n, we are trying to assign the memory address of n to x which is not allowed. The reason is the name x is not lvalue and we cannot assign any value to it. For understanding purposes, consider xas a constant. Its name or memory location can not be changed. This is a collective name for six locations. We can access these locations as x[0], x[1] up to x[5]. This is the way arrays are manipulated.
Sometimes, you would like to use an array data structure but may lack the information about the size of the array at compile time. Take the example of telephone directory. You have to store one lakh (100,000) names in an array. But you never know that the  number of  entries may get double or decline in future. Similarly, you cannot say that the total population of the country is one crore (10 million) and declare an array of one crore names. You can use one lakh locations now and remaining will be used as the need arrives. But this is not a good way of using the computer resources. You have declared a very big array while using a very small chunk of it. Thus the remaining space goes waste which can, otherwise, be used by some other programs. 
Suppose you need an integer array of size n after the execution of the program. We have studied that if it is known at the execution of the program that an array of size 20 or 30 is needed, it is allocated dynamically. The programming statement is as follows:
            int*  y = new int[20]; 
It means we are requesting computer to find twenty memory locations. On finding it, the computer will give the address of first location to the programmer which will be stored in   y. Arrays locations are contiguous i.e. these are adjacent. These twenty locations will be contiguous, meaning that they will be neighbours to each other. Now yhas become an array and we can say y[0] =1 or y[5] = 15. Here y is an lvalue. Being a pointer, it is a variable where we can store the address of some variable. 
When we said , int* y = new int[20];
The new returns the memory address of first of the twenty locations and we store that address into y. As y is a pointer variable so it can be used on the left-hand side. We can write it as:
            y = &x[0];  

In the above statement, we get the address of the first location of the array x and store it in y. As y is lvalue, so it can be used on left hand side. This means that the above statement is correct.
            y = x;
Similarly, the statement y = x is also correct. x is an array of six elements that holds the address of the first element. But we cannot change this address. However we can get that address and store it in some other variable. As y is a pointer variable and lvalue so the above operation is legal. We have dynamically allocated the memory for the array. This memory, after the use, can be released so that other programs can use it. We can use the delete keyword to release the memory. The syntax is:
            delete[ ] y;
We are releasing the memory, making it available for use by other programs. We will not do it in case of xarray, as ‘new’ was not used for its creation. So it is not our responsibility to delete x

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